### Warm-up:

Perimeter Questions

(care of corbettmaths.com)

### The Problem:

-/|\-

### Solution:

## ... To Follow ...

As the shape is declared to be a rectangle, then ...

$$y=x-14$$and

$$x=2y+2$$Rearranging the second equation to the same structure as the first.

$$2y=x-2$$Subtracting the first equation from the second

$$y=12$$Substituting this into the first equation

$$12=x-14$$ $$x=26$$The perimeter of a rectangle is given by

$$P=2(l+w)$$ $$P=2(x-14+x)$$ $$P=4x-28$$ $$P=76$$-oOo-

### Further Reading:

Simultaneous Equations

(care of mmerevise.co.uk)